The most direct way to allocate an object in an obstack is with obstack_alloc , which is invoked almost like malloc .
struct obstack object which represents the obstack. Each obstack function or macro requires you to specify an obstack-ptr as the first argument.
This function calls the obstack's obstack_chunk_alloc function if it needs to allocate a new chunk of memory; it returns a null pointer if obstack_chunk_alloc returns one. In that case, it has not changed the amount of memory allocated in the obstack. If you supply an obstack_chunk_alloc function that calls exit (see Program Termination) or longjmp (see Non-Local Exits) when out of memory, then obstack_alloc will never return a null pointer.
For example, here is a function that allocates a copy of a string str in a specific obstack, which is in the variable string_obstack :
struct obstack string_obstack;
char *
copystring (char *string)
{
char *s = (char *) obstack_alloc (&string_obstack,
strlen (string) + 1);
memcpy (s, string, strlen (string));
return s;
}
To allocate a block with specified contents, use the function obstack_copy , declared like this:
obstack_alloc .
obstack_copy , but appends an extra byte containing a null character. This extra byte is not counted in the argument size.
The obstack_copy0 function is convenient for copying a sequence of characters into an obstack as a null-terminated string. Here is an example of its use:
char *
obstack_savestring (char *addr, int size)
{
return obstack_copy0 (&myobstack, addr, size);
}
Contrast this with the previous example of savestring using malloc (see Basic Allocation).